0=-36t^2+600t

Solution for 0=-36t^2+600t equation:

0=-36t^2+600t

We move all terms to the left:

0-(-36t^2+600t)=0

We add all the numbers together, and all the variables

-(-36t^2+600t)=0

We get rid of parentheses

36t^2-600t=0

a = 36; b = -600; c = 0;
Δ = b2-4ac
Δ = -6002-4·36·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{360000}=600$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-600}{2*36}=\frac{0}{72}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+600}{2*36}=\frac{1200}{72}
=16+2/3
$